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Which product do you expect from the rea...

Which product do you expect from the reaction ?
`CH_(3) - overset(CH_(3))overset(|)(C) = CH_(2) underset((ii)H_(2)O_(2),OH)overset((i) (BH_(3))_(2))rarr`

A

`CH_(3) - overset(CH_(3))overset(|)(CH) - CH_(2)OH`

B

`CH_(3) - underset(OH)underset(|)overset(CH_(3))overset(|)(C) - CH_(3)`

C

`CH_(3) - underset(OH)underset(|)(CH) - overset(CH_(3))overset(|)(CH_(2))`

D

`CH_(3) - underset(CH_(3))underset(|)(CH) - CHO`

Text Solution

Verified by Experts

The correct Answer is:
A
`CH_(3) - overset(CH_(3))overset(|)(C) = CH_(2) underset(H_(2)O_(2),OH)overset((BH_(3))_(2))rarr CH_(3) - underset(H)underset(|)overset(CH_(3))overset(|)(C) - CH_(2)OH`
This reaction proceeds as
`CH_(3)overset(CH_(3))overset(|)(C) = CH_(2) + BH_(3) rarr underset("Trialkyl borane")([(CH_(3))_(2)CHCH_(2)]_(3)B) underset(OH^(-))overset(H_(2)O_(2))rarr underset("Alcohol")(3(CH_(3))_(2) CHCH_(2)OH`
The overall result of the reaction is anti-Markovnikov.s addition of `H_(2)O` to a double bond. This is called hydroboration reaction.
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