Propanol is heated with conc. `H_(2)SO_(4)` at `170^(@)C` and the gas produced is reacted with HBr. What is the formula of the final product ?

Options

A. `CH_(3) - CH_(2) CH_(2)Br`
B. `CH_(3) underset(Br)underset(|)(CH)-underset(Br)underset(|)(CH_(2))`
C. `CH_(3) - underset(Br)underset(|)(CH) - CH_(2)OH`
D. `CH_(3) - underset(Br)underset(|)(CH) - CH_(3)`

Answer

D

Explanation

Dehydration of propanol with conc. `H_(2)SO_(4)` gives propene which reacts with HBr to form
`CH_(3) underset(Br)underset(|)(CH) - CH_(3)` (Markovnikov.s rule).