2-Chlorobutane was treated with alc. KOH and the product formed was reacted with dil. `KMnO_(4)` to give the product B. The structure of B is :

Options

A. `CH_(3) - underset(OH)underset(|)(CH) - CH_(2) - CH_(3)`
B. `CH_(3) - CH = CH - CH_(2)OH`
C. `CH_(3) - underset(OH)underset(|)(CH) - underset(OH)underset(|)(CH)CH_(3)`
D. `underset(OH)underset(|)(CH_(2)) - underset(OH)underset(|)(CH)CH_(2)CH_(3)`

Answer

C

Explanation

`CH_(3) - CH_(2) underset(Cl)(CH)CH_(3) overset(alk.KOH)rarr CH_(3)CH = CHCH_(3) overset(alk.KMnO_(4))rarr CH_(3) - underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH) - CH_(3)`