In the following reaction : `RCH_(2)CH = CH_(2) + Icl rarr [A]` Markovinkoff's product [A] is :

Options

A. `RCH_(2)underset(Cl)underset(|)(CH) - CH_(2)I`
B. `RCH_(2) - underset(I)underset(|)(CH) - CH_(2)Cl`
C. `RCH - underset(I)(CH) = CH_(2)`
D. `RCH = CH - CH_(2)I`

Answer

A

Explanation

`RCH_(2)CH = CH_(2) + ICl rarr RCH_(2) - underset(Cl)underset(|)(CH) - CH_(2)I`
In accordance with Markovnikov.s rule, more electronegative chlorine atom goes to the carbon with lesser number of hydrogens.