Home
Class 12
CHEMISTRY
A metallic element 'X' has cubic lattic....

A metallic element 'X' has cubic lattic. Each edge of the unit cell is `2.0Å` and its density is 2.5 `g cm^(-3)`. Number of atoms in 200g of the metal are `:`

A

`1 xx 10^(20)`

B

`1 xx 10^(22)`

C

`1 xx 10^(24)`

D

`1 xx 10^(25)`

Text Solution

Verified by Experts

The correct Answer is:
D

Volume of unit cell `= ( 2.0 xx 10^(-8) cm )^(3)`
`= 8 xx 10^(-24) cm^(3)`
Density `= 2.5 g cm^(-3)`
Mass of unit cell `= 8 xx 10^(-24) xx 2.5 `
`= 20 xx 10^(-24) g `
No. of unit cells in 200g `= ( 200)/( 20 xx 10^(-24))`
`= 1 xx 10^( 25)`
Since metallic element has simple cubic lattice, number of atoms in a unit cell =1
No. of atoms in 200g of metal
`=1 xx 10^(25) xx 1 `
`= 1 xx 10^(25) ` atoms
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (LEVEL -II )|40 Videos
  • THE SOLID STATE

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (LEVEL -III )|10 Videos
  • SURFACE CHEMISTRY

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTIONS|15 Videos
  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Recent Examination Question|15 Videos

Similar Questions

Explore conceptually related problems

A metallic element exists as a cubic lattice. Each edge of the unit cell is 2.88 Å . The density of the metal is 7.20 g cm^(-3) . How many unit cells there will be in 100g of the metal?

The cell edge of a fcc crystal is 100 pm and its density is 10.0 g cm^(-3) . The number of atoms in 100 g of this crystal is :

An element crystallizes in fcc lattice. If the edge length of the unit cell is 408.6 pm and the density is 10.5 g cm^(-3) . Calculate the atomic mass of the element.

A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm^(-3) . The molar mass of the metal is (N_A,"Avogadro's constant"=6.02 X10^23 mol^(-1))

An element crystallized in fcc lattice and edge length of unit cell is 400 pm. If density of unit cell is 11.2 g cm^(-3) , then atomic mass of the element is

A metal crystallizes with a face-centred cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is

A metal crystallises with a face-centred cubic lattice. The adge of the unit cell is 408 pm. The diameter of the metal atom is :

An element has a bcc structure with a celledge of 288 pm. The density of the element is 7.2 g cm^(-3) . How many atins are present in 208 g of the element?

Li forms a body-centred cubic lattice. If the edge of the cube is 3.5 xx 10^(-10)m and the density is 5.3 xx 10^(2) kg m^(-3) , calculate the percentage occupancy of Li metal.

The well known mineral fluorite is chemically calcium fluoride. It is known that in one unit cell of this mineral there are 4 Ca^(2+) ions and 8F^(-) ions and that Ca^(2+) ions are arranged in a fcc-lattice. The F^(-) ions fill all the tetrahedral holes in the face centred cubic lattice of Ca^(2+) ions. The edge of the unit cell is 5.46 xx 10^(-8) cm in length. The density of the solid is 3.18 g cm^(-3) . Use this information to calculate Avogadro's number. (Molar mass of CaF_(2) = 78.08 g mol^(-1) )