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Volume occupied by single CsCl ion pair ...

Volume occupied by single CsCl ion pair in a crystal is `7.014 xx 10^(-23) c^(3)`. The smallest Cs-Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly

A

`4.4 Å`

B

`4.3Å`

C

`4Å`

D

`4.5Å`

Text Solution

Verified by Experts

The correct Answer is:
C
Here, `a^(3) = 7.014 xx 10^(-23) cm^(3)`
`a = ( 7.04 xx 10^(-23))^(1//3)`
`= 4.124 xx 10^(-8)` cm
`= 4.124 xx 10^(-10)` m `= 4.124 Å ~~ 4 Å`
`:.` Smallest internuclear distance of Cs-Cs is 4.124 `Å` or nearly `4Å`
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