The ration of the time required for 3/4 of the reaction and half of the reaction is :

Options

A. `4:3 `
B. `3:2`
C. `2:1`
D. `1:2`

Answer

C

Explanation

(C ) Time required for 3/4 of reaction
`t_(3//4) = (2.303)/(k) "log" (a)/(1//4a) = (2.303)/(k) log 4 `
Time required for half of reaction
`t_(1//2) = (2.303)/(k ) "log" (a)/((1)/(2)a)=(2.303)/(k)"log"2`
`(t_(3//4))/(t_(1//2))=("log"4)/("log"2)=(2"log"2)/("log2)=2:1`