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The rate constant for a fist order react...

The rate constant for a fist order reaction is `k = 7xx10^(-4)s^(-1)` .The time taken for the reactant to be reduced to 1/2 of the initial concentration is :

A

990 s

B

1980 s

C

445 s

D

2970 s

Text Solution

Verified by Experts

The correct Answer is:
B
(B) `t=(2.303)/(k)"log"(1a)/(1//4a)`
`=(2.303)/(7xx10^(-4))"log"4 `
`t=(2.303)/(7xx10^(-4))xx0.0602`
= 1980 s
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MODERN PUBLICATION-CHEMICAL KINETICS -Multiple Choice Questions ( Measuring Order of a Reaction : Integrated rate equation half life period )
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