A radioactive substance is reduced to 1/8 of its original concentration in 24 s. The rate constant of the reaction is :

Options

A. `(0.69)/(16) s^(-1)`
B. `(1)/(8)s^(-1)`
C. `(1)/(24)s^(-1)`
D. `("In"2)/(8)s^(-1)`

Answer

D

Explanation

(D ) `([A]_(0))/(2^(n)) = ([A]_(0))/(8) " ""or"" " 2^(n) =8 , n =3 `
`t_(1//2) = (24)/(3) = 8s`
`k = (In2)/(8) s^(-1)` .