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The half life period of the reaction : ...

The half life period of the reaction :
`N_(2) O_(5) rarr 2NO_(2) +(1)/(2) O_(2)`
is 24 hrs at `30^(@) C ` . Starting with 10 g of `N_(2) O_(5)` how many grams of `N_(2) O_(5)` will remain after a period of 96 hours ?

A

`1.25 g `

B

`0.63 g`

C

`1.75 g `

D

`0.5 g`

Text Solution

Verified by Experts

The correct Answer is:
D

No. of half life periods =4
Amount left `=([A]_(0))/(2^(n))=(10)/(2^(4))=0.63 g `
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