For a chemical raction `AtoB` the rate of the reaction is `2xx10^(-3)` mol `dm^(-3)s^(-1)`, when the initial concentration is 0.05 mol `dm^(-3)`. The rate of the same reaction is `1.6xx10^(-2)` mol `dm^(-3)s^(-1)` when the initial concentration is 0.1 mol `dm^(-3)`. The order of the reaction is

Options

A. 0
B. 3
C. 1
D. 2

Answer

B

Explanation

(B ) Initial concentration `" " ` Rate of reaction
(mol /`dm^(3))" "` (mol/`dm^(3)`/s )
`0.05 " " 2xx10^(-3)`
`0.10 " "1.6xx10^(-2)`
It can be seen from above data that the rate of reaction becomes 8 times when the initial concentration is doubled . Therefore order of reaction is 3 .