A coordination complex compound of cobalt has molecular formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three mole ions in an aqueous solution. On reacting this solution with excess of silver nitrate solution, two moles of AgCl get precipitated. The formula of this compound would be

Options

A. `[Co(NH_(3))_(4)(NO_(2))Cl][NH_(3)Cl]`
B. `[Co(NH_(3))_(5)Cl][Cl(NO_(2))]`
C. `[Co(NH_(3))_(5)(NO_(2))]Cl_(2)`
D. `[Co(NH_(3))_(5)][(NO_(2))Cl_(2)]`

Answer

C

Explanation

`[Co(NH_(3))_(5)Cl]Cl_(2) hArr [Co(NH_(3))_(5)Cl]^(2+)+2Cl^(-)` three ions. With `AgNO_(3)`, it gives 2 moles of AgCl.