The "spin only" magnetic moment of `Ni^(2+)` in aqueous solution would be [At No. of Ni = 28]

Options

A. `4.90`
B. 0
C. 1.73
D. 2.84

Answer

D

Explanation

`Ni^(2+)` in aqueous solution exists as `[Ni(H_(2)O)_(6)]^(2+)`. It has `sp^(3)d^(2)` hybridisation as:
`Ni(II):3d^(8)4s^(0)`

No. of unpaired electron = 2
`mu_(s)=sqrt(n(n+2))=sqrt(2(2+2))=2sqrt(2)=2.84 B.M.`