2-Propanol reacts with sulphuric acid at `170^(@)C`, gives an alkene which reacts with bromine to give dibromoalkane. Alcoholic potassium hydroxide dehydrogenates the dibromo product to X. The structure of X is :

Options

A. `CH_(2)=CH-CH_(3)`
B. `CH_(3)-underset(Br)underset("| ")(CH)=CH_(2)Br`
C. `CH_(3)-C-=CH`
D. `underset(Br)underset("| ")(CH_(2))-C-=CH`

Answer

C

Explanation

`CH_(3)underset(OH)underset("| ")(CH)CH_(3)underset(170^(@)C)overset(H_(2)SO_(4))rarrCH_(3)CH=CH_(2)overset(Br_(2))rarrCH_(3)underset(Br)underset("| ")(CH)-underset(Br)underset("| ")(CH_(2))overset("alc. KOH")rarrunderset((X))(CH_(3)C-=CH)`