During the conversion: C(6)H(5)CH(2)CH...

During the conversion:
`C_(6)H_(5)CH_(2)CH_(3)overset((a))rarrXoverset((b))rarrC_(6)H_(5)CH=CH_(2)`
the reagents (a) and (b) are respectively

A

`SOCl_(2)`, alc. KOH

B

`Cl_(2)//hv, H_(2)O`

C

`SO_(2)Cl_(2)`, aq. KOH

D

`SO_(2)Cl_(2)`, alc. KOH

Text Solution

Verified by Experts

The correct Answer is:

D

`C_(6)H_(5)CH_(2)CH_(3)underset(-SO_(2),-HCl)overset(SO_(2)Cl_(2)(a))rarrC_(6)H_(5)underset(Cl)underset(|)(C)HCH_(3)underset(-HCl)overset("alc. KOH(b)")rarrC_(6)H_(5)CH=CH_(2)`

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