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CH(3)Br+Nu^(-)rarrCH(3)Nu+Br^(-) The d...

`CH_(3)Br+Nu^(-)rarrCH_(3)Nu+Br^(-)`
The decreasing order of the rate of the above reaction with nucleophiles `(Nu^(-))` I to IV is :
`[Nu^(-)=(I)PhO^(-),(II)AcO^(-),(III)HO^(-),(IV)CH_(3)O^(-)]`

A

`IVgtIIIgtIIgtI`

B

`IgtIIgtIIIgtIV`

C

`IIgtIVgtIIIgtI`

D

`IVgtIIIgtIgtII`

Text Solution

Verified by Experts

The correct Answer is:
D
The reaction follows `S_(N)2` mechanism so stronger the base, the better its nucleophilicity as :
`CH_(3)O^(-)gtOH^(-)gtPhO^(-)gtAcO^(-)`
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