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A can complete a piece of work working along with B in 20 days. If he can complete the same work working along with C in 10 days, then between B and C who is more efficient ?

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To solve the problem step by step, we will determine the efficiencies of A, B, and C based on the information provided. ### Step-by-Step Solution: **Step 1: Determine the total work done.** Assume the total work is 20 units (this is a convenient number based on the days given). **Hint for Step 1:** Start by assuming a total work amount that makes calculations easier, such as 20 units. **Step 2: Calculate the efficiency of A and B together.** Since A and B can complete the work in 20 days: - Efficiency of A + B = Total Work / Days = 20 units / 20 days = 1 unit per day. **Hint for Step 2:** Use the formula: Efficiency = Total Work / Time taken to find how much work is done together. **Step 3: Calculate the efficiency of A and C together.** Since A and C can complete the work in 10 days: - Efficiency of A + C = Total Work / Days = 20 units / 10 days = 2 units per day. **Hint for Step 3:** Again, apply the same formula to find the combined efficiency of A and C. **Step 4: Determine A's efficiency.** Let A's efficiency be 'a', B's efficiency be 'b', and C's efficiency be 'c'. From the previous steps: - A + B = 1 unit/day (Equation 1) - A + C = 2 units/day (Equation 2) **Hint for Step 4:** Use variables to represent the efficiencies of A, B, and C for easier calculations. **Step 5: Solve for A's efficiency using the equations.** From Equation 1: - A + B = 1 - Therefore, B = 1 - A (Equation 3) From Equation 2: - A + C = 2 - Therefore, C = 2 - A (Equation 4) **Hint for Step 5:** Rearrange the equations to express B and C in terms of A. **Step 6: Substitute A's efficiency to find B and C.** We know from the equations: - If we assume A's efficiency is 'a', we can substitute 'a' into Equations 3 and 4 to find B and C. **Step 7: Compare the efficiencies of B and C.** - From Equation 3: B = 1 - a - From Equation 4: C = 2 - a To find out who is more efficient, we compare B and C: - If C > B, then C is more efficient. - If 2 - a > 1 - a, then C is more efficient. **Step 8: Simplify the comparison.** - Simplifying gives us: 2 - a > 1 - a - This simplifies to: 2 > 1, which is always true. **Conclusion:** C is more efficient than B. **Final Answer:** C is more efficient than B.
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