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Six men and 4 women can do a piece of wo...

Six men and 4 women can do a piece of work in 32 days. Seven men and 12 women can do it in 18 days. In how many days can 18 men and 8 women do the same work, working together ?

A

10

B

12

C

14

D

16

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The correct Answer is:
To solve the problem, we need to find out how many days 18 men and 8 women can complete the same work when working together. We will first establish the work rates of men and women based on the information given. ### Step 1: Establish the work done by men and women Let the work done by one man in one day be \( m \) and the work done by one woman in one day be \( w \). From the first piece of information: - 6 men and 4 women can complete the work in 32 days. This means the total work \( W \) can be expressed as: \[ W = (6m + 4w) \times 32 \] From the second piece of information: - 7 men and 12 women can complete the work in 18 days. This means the total work \( W \) can also be expressed as: \[ W = (7m + 12w) \times 18 \] ### Step 2: Set the two equations for total work equal to each other Since both expressions equal the total work \( W \), we can set them equal to each other: \[ (6m + 4w) \times 32 = (7m + 12w) \times 18 \] ### Step 3: Simplify the equation Expanding both sides gives: \[ 192m + 128w = 126m + 216w \] ### Step 4: Rearranging the equation Now, we can rearrange the equation to isolate \( m \) and \( w \): \[ 192m - 126m = 216w - 128w \] \[ 66m = 88w \] ### Step 5: Find the relationship between men and women Dividing both sides by 22 gives: \[ 3m = 4w \quad \Rightarrow \quad m = \frac{4}{3}w \] ### Step 6: Substitute \( m \) back into one of the original equations Now, we can substitute \( m \) into one of the total work equations. Let's use the first one: \[ W = (6m + 4w) \times 32 \] Substituting \( m \): \[ W = \left(6 \times \frac{4}{3}w + 4w\right) \times 32 \] \[ = \left(8w + 4w\right) \times 32 = 12w \times 32 = 384w \] ### Step 7: Find the work done by 18 men and 8 women Now, we need to find how many days 18 men and 8 women can complete the work: \[ W = (18m + 8w) \times D \] Substituting \( m \): \[ W = \left(18 \times \frac{4}{3}w + 8w\right) \times D \] \[ = \left(24w + 8w\right) \times D = 32w \times D \] ### Step 8: Set the two expressions for work equal Now we can set the two expressions for \( W \) equal to each other: \[ 384w = 32w \times D \] ### Step 9: Solve for \( D \) Dividing both sides by \( 32w \): \[ D = \frac{384}{32} = 12 \] Thus, **18 men and 8 women can complete the work in 12 days.**

To solve the problem, we need to find out how many days 18 men and 8 women can complete the same work when working together. We will first establish the work rates of men and women based on the information given. ### Step 1: Establish the work done by men and women Let the work done by one man in one day be \( m \) and the work done by one woman in one day be \( w \). From the first piece of information: - 6 men and 4 women can complete the work in 32 days. This means the total work \( W \) can be expressed as: ...
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PEARSON IIT JEE FOUNDATION-TIME AND WORK PIPES AND CISTERNS-CONCEPT APPLICATION (LEVEL-1)
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