Home
Class 12
MATHS
Find the area bounded by the curve x^2=y...

Find the area bounded by the curve `x^2=y ,x^2=-ya n dy^2=4x-3`

Text Solution

Verified by Experts

The given curves are
`x^(2)=y" (1)"`
`x^(2)=-y" (2)"`
`y^(2)=4x-3" (3)"`
Clearly (1) and (2) meet at (0,0).
Solving (1) and (3), we get `x^(4)-4x+3=0`
`"or "(x-1)(x^(3)+x^(2)+x-3)=0`
`"or "(x-1)^(2)(x^(2)+2x+3)=0`
`rArr" "x=1 rArr y=1`
Thus, point of intersection is (1,1)
Similarly, point of intersection of (2) and (3) is (1,-1).
The graphs of three curves are as shown in the figure.

We also observe that at `x=1 andy y=1, (dy)/(dx)" for "(1) and (3)` is same
and hence the two curves touch each other at (1,1).
Same is the case with (2) and (3) at (1,-1).
Required area = Shaded region in the figure
`=2(Ar" "OPQA)`
`2[int_(0)^(1)x^(2)dx-int_(3//4)^(1)sqrt(4x-3)dx]`
`=2[((x^(2))/(3))_(0)^(1)-((2(4x-3)^(3//2))/(4xx3))_(3//4)^(1)]=2[(1)/(3)-(1)/(6)]`
`=(1)/(3)` sq. units.
Promotional Banner

Topper's Solved these Questions

  • AREA

    CENGAGE|Exercise Exercise 9.1|9 Videos
  • AREA

    CENGAGE|Exercise Exercise 9.2|14 Videos
  • APPLICATIONS OF DERIVATIVES

    CENGAGE|Exercise Question Bank|29 Videos
  • AREA UNDER CURVES

    CENGAGE|Exercise Question Bank|20 Videos

Similar Questions

Explore conceptually related problems

Find the area bounded by the curves x^(2)=yx^(2)=-y and y^(2)=4x-3

Find area bounded by the curves x^(2)<=y<=x+2

Find the area bounded by the curves x+2|y|=1 and x=0

Find the area bounded by the curves y=x^(3)-x and y=x^(2)+x.

Find the area bounded by the curve 4y^(2)=9x and 3x^(2)=16y

Find the area bounded by the curve y=4x^(2),x=0,x=1 and y=4 in first quadrant.

Find the area bounded by the curve x^(2)=4y and the line x=4y-2

Find the area bounded by the curves x^(2)+y^(2)=4 and x^(2)+y^(2)=4x

Find the area bounded by the curves x^(2)+y^(2)=4, x^(2)=-sqrt(2)y and x = y.

Find the area bounded by the curve y=x^2+2x-3 and the line y=x+3 .