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If the area enclosed by the curve y=sqrt...

If the area enclosed by the curve `y=sqrt(x)` and `x=-sqrt(y)` , the circle `x^2+y^2=2` above the x-axis is `A ,` then the value of `(16)/piA` is___

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The correct Answer is:
8
Required area = Area of one quadrant of the circle `=pi//2`
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