Draw the graph of the function `f(x) =x-sqrt(x)`.

Explanation

We have `f(x) = x-sqrt(x)`
Clearly, the domain of the function is `[0, pi)`
`f(x) = sqrt(x) (sqrt(x)-1)`
`f(x) lt 0` for `x lt 1` and
`f(x) lt 0` for `0 lt x lt 1`
Also `f(0) =0` and
`f(x) =0 therefore x=0,1`
The graph intersects the x-axis at (0,0) and (1,0)
Now, `f^(')(x) = 1-1/(2sqrt(x)) = (2sqrt(x)-1)/(2sqrt(x))`
`f^(')(x) =0 therefore x=1//4`, which is the point of minima.
`f(1//4)=-1//4`
Further when `x to infty, x-sqrt(x) to infty`
Thus, from point `O(0,0)` to `p(1//4, -1//4),f(x)` decreases from 0 to `-1//4`
From P onwards, `f(x)` increases, intersecting the x-axis at `Q(1,0)`.
Hence the graph of the function is as shown in the following figure.