Draw the graph of `y=sqrt((1-x)/(1+x))`.

Explanation

We have `y=f(x) = sqrt((1-x)/(1+x))`
`f(x)` is defined if `(1-x)/(1+x) ge0`
`therefore (x-1)/(x+1) le0`
`therefore -1 lt x le1`
`f(0)=1`
`f(x) =0 therefore x=1`
`f(x)=0 therefore x=1`
`f^(')(x) = 1/2sqrt((1+x)/(1-x)) . -2/(1+x)^(2) lt 0, AA x in (-1,1)`
Thus, `f(x)` decreases in the entire domain.
Also, `underset(xto -1^(+))sqrt((1-x)/(1+x))=infty`
Thus, `f(x)` decreases from `infty` in `(-1,1)`, intersecting the y-axis at (0,1).
Thus, the graph of `y-=f(x)` can be drawn as shown in the following figure.