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Consider an ellipse x^2/25+y^2/9=1 with...

Consider an ellipse `x^2/25+y^2/9=1` with centre c and a point P on it with eccentric angle `pi/4.` Nomal drawn at P intersects the major and minor axes in `A and B` respectively. `N_1 and N_2` are the feet of the perpendiculars from the foci `S_1 and S_2` respectively on the tangent at P and N is the foot of the perpendicular from the centre of the ellipse on the normal at P. Tangent at P intersects the axis of x at T.

A

`{:(P,Q,R,S),(2,3,4,1):}`

B

`{:(P,Q,R,S),(3,1,4,2):}`

C

`{:(P,Q,R,S),(2,4,1,3):}`

D

`{:(P,Q,R,S),(4,1,2,3):}`

Text Solution

Verified by Experts

The correct Answer is:
C

(p) `(CA)(CT) = (e^(2)a cos theta) ((a^(2))/(a cos theta)) = a^(2) -b^(2) = 16`
(q) `(PN) (PB) = a^(2) = 25`
(r) `(S_(1)N_(1)) (S_(2)N_(2)) = b^(2) = 9`
(s) `(S_(1)P) (S_(2)P) = [a + e(a cos theta)] [a-e(a cos theta)] = a^(2) sin^(2) theta + b^(2) cos^(2) theta = 17`
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