If `sin 2theta + sin 2phi =1/2` and `cos 2theta+cos 2phi=3/2`, then `cos^2(theta-phi)=`

If sin 2theta+sin 2phi=1//2 and cos2theta+cos 2phi=3//2 , then cos^(2)(theta-phi)=

If sin 2theta+sin 2phi=1//2 and cos2theta+cos 2phi=3//2 , then cos^(2)(theta-phi)=

If sin 2theta+sin 2phi=1//2 and cos2theta+cos 2phi=3//2 , then cos^(2)(theta-phi)=

If sin 2 theta + sin 2 phi =1/2 and cos 2 theta + cos 2 phi =3/2, then cos ^(2) (theta - phi)=

If sin 2 theta + sin 2 phi =1/2 and cos 2 theta + cos 2 phi =3/2, then cos ^(2) (theta - phi)=

If sim 2theta+sin2phi=1/2 and cos 2theta+cos2phi=3/2 then cos^2(theta-phi)=

If sin2 theta+sin2 phi=(1)/(2) and cos2 theta+cos2 phi=(3)/(2), then cos^(2)(theta-phi)=(A)(3)/(8)(B)(5)/(8)(C)(3)/(4)(D)(5)/(4)

If sin 2 theta+sin 2 phi=(1)/(2) and cos 2 theta+cos 2 phi=(3)/(2) then cos ^(2)(theta-phi)=

If sin theta - sin phi = a and cos theta + cos phi = b then prove that cos(theta + phi) = (a^(2)+b^(2) -2)/2

If sin theta +sin phi=a and cos theta +cos phi =b then prove cos (theta +phi)=(b^(2)-a^(2))/(b^(2)+a^(2))