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sin (x^(2) + 5)...

`sin (x^(2) + 5)`

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To differentiate the function \( y = \sin(x^2 + 5) \) with respect to \( x \), we will use the chain rule. Here’s a step-by-step solution: ### Step 1: Identify the outer and inner functions We have: - Outer function: \( \sin(u) \) where \( u = x^2 + 5 \) - Inner function: \( u = x^2 + 5 \) ### Step 2: Differentiate the outer function ...
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