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For the reaction CH(3)COCH(3)+Br(2)ove...

For the reaction
`CH_(3)COCH_(3)+Br_(2)overset(H^(+))toCH_(3)COCH_(2)Br+H^(+)+Br^(-)`
the following data was collected
`{:(["Acctone"],[Br_(2)],[H^(+)],"Rate of reaction "(Ms^(-1)),),(" "0.15,0.025,0.025," "6xx10^(-4),),(" "0.15,0.050,0.025," "6xx10^(-4),),(" "0.15,0.025,0.050," "12xx10^(-4),),(" "0.20,0.025,0.025," "8.0xx10^(-4),):}`
Calculate order of the reaction w.r.t. `CH_(3)COCH_(3)andBr_(2)`

Text Solution

Verified by Experts

`"Rate"=k."[Acetone]"^(x).[Br_(2)]^(y).[H]^(z)`
`6xx10^(-4)=k.(0.15)^(x)(0.025)^(y)(0.025)^(z)` . . . .(i)
`6xx10^(-4)=k.(0.15)^(x)(0.050)^(y)(0.025)^(z)` . . . .(ii)
`12xx10^(-4)=k.(0.15)^(x)(0.025)^(y)(0.050)^(z)` . . . .(iii)
`8xx10^(-4)=k.(0.20)^(x)(0.025)^(y)(0.025)^(z)` . . . .(iv)
(i) `divide` (ii), `1((0.025)/(0.050))^(y)`
y=0, hance rate does not depend upon the concentration of `Br_(2)`.
(i) `divide` (iii), `(6)/(12)=((0.025)/(0.050))^(z),(1)/(2)=((1)/(2))^(z)`
`:.z=1`
(i) `divide` (iv), `(3)/(4)=((3)/(4))^(x)`
`:.x=1" "]`
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