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If A = [{:(2, 3, -1),(5, 6, 1):}], then ...

If A = `[{:(2, 3, -1),(5, 6, 1):}]`, then find (0) -A (b) 3A (c) `(1)/(4)A`.

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(a) -A = `[{:(2, 3, -1),(5, 6, 1):}] = [{:(-1 xx 2, -1 xx 3, -1 xx (-1)),(-1 xx 5, -1 xx 6, -1 xx 1):}] = [{:(-2, -3, 1),(-5, -6, -1):}]`
(b) `3A = 3[{:(2, 3, -1),(5, 6, 1):}] = [{:(3 xx 2, 3 xx 3, 3 xx (-1)),(3 xx 5, 3 xx 6, 3 xx 1):}] = [{:(6, 9, -3),(15, 18, 3):}]`
(c) ` (1)/(4)A = (1)/(4) [{:(2, 3, -1),(5, 6, 1):}] = [{:((1)/(4) xx 2, (1)/(4) xx 3, (1)/(4) xx (-1)), ((1)/(4) xx 5, (1)/(4) xx 6, (1)/(4) xx 1):}] = [{:((1)/(2), (3)/(4), (-1)/(4)), ((5)/(4), (3)/(2), (1)/(4)):}]`
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