At a particular time , the shadow cast b...

At a particular time , the shadow cast by a tower is 6 m long. If the distance from the top of the tower to the end of the shadow is 10 m long, determine the height of the tower.

4 m

8 m

16 m

12 m

Text Solution

Verified by Experts

The correct Answer is:

(i) Apply 'Pythagoras theorem'.
(ii) The towar is perpendicular to the surface of the ground.

Topper's Solved these Questions

GEOMETRY
PEARSON IIT JEE FOUNDATION|Exercise Concept Application Level -3|15 Videos
GEOMETRY
PEARSON IIT JEE FOUNDATION|Exercise Concept Application Level -1|34 Videos
BANKING
PEARSON IIT JEE FOUNDATION|Exercise LEVEL 3|10 Videos
LIMITS
PEARSON IIT JEE FOUNDATION|Exercise LEVEL-3|15 Videos

Similar Questions

Explore conceptually related problems

A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.

A tree 6m tall casts a shadow 4m long.At the same time if a tower casts the shadow 10m long then find the height of the tower.

A vertical stick 10cm long casts a shadow 8cm long.At the same time a tower casts a shadow 30m long.Determine the height of the tower.

At a particular instant the height of the tower is equl to the length of its shadow after some time the length of the shadow is sqrt(3) xx of the height of the tower,then the time lapsed between the two observations in hours is

A vertical stick 12m long casts a shadow 8m long on the ground.At the same time a tower casts the shadow 40m long onthe ground. Determine the height of the tower.

A tower subtends a right angle at the top of the hillock and the angle of elevation of the top of the hillock from the bottom of the tower is 60^(@) . If the distance between the tower and the hillock is 6m ,then the height of the tower is

A body thrown horizontally from the top of a tower touches the ground at a distance of 160m from the foot of the tower.If the velocity of projection is 40m/s then the height of the tower is (g=9.8m/s^(2))

The horizontal distance between two towers is 140m .The angle of elevation of the top of the first tower when seen from the top of the second tower is 30^(0). If the height of the second tower is 60m ,find the height of the first tower.

The horizontal distance between two towers is 140m. The angle of elevation of the top of the first tower when seen from the top of the second tower is 30^(0). If the height of the second tower is 60m, find the height of the first tower.

PEARSON IIT JEE FOUNDATION-GEOMETRY-Concept Application Level -2

. In the figure given below, ABC is an equilateral triangleand PQRS is...
Text Solution
|
In the following figure (not a scale ) ABCD is a rectangle , BC =24 c...
Text Solution
|
At a particular time , the shadow cast by a tower is 6 m long. If the ...
Text Solution
|
In the following figure, angle ABC =90^@ , AD=15 and DC=20.If BD is th...
Text Solution
|
In the triangle ABC, angle ABC or angle B =90^@. AB : BD :DC =3:1:3. I...
Text Solution
|
In the following figure, find AD.
Text Solution
|
In the given figure, AB is a diameter, O is the center of the circle ...
Text Solution
|
In the following fiure. O is the centr of the circle and AD is the dia...
Text Solution
|
In the following figure, O is the centre of the circle , AC is the dia...
Text Solution
|
In the trapezium PQRS, PQ is parallel to RS and the ratio of the areas...
Text Solution
|
In the following figure ,ABCD is a parallelogram, CB is extended to F ...
Text Solution
|
PQR is a right angled tringle , where angle P=90^@, overline(PD) is pe...
Text Solution
|
Two circles intersect at two points P and S. QR is a tangent to the tw...
Text Solution
|
An equilateral triangle CDE is constructed on a side CD of sqaure ABCD...
Text Solution
|
In the figure above (not to scale), PQ is a tangent segment to the cir...
Text Solution
|
Construct the incircle of a given triangle ABC. The following sentence...
Text Solution
|
Construct a regular pentagon in a circle of radius 4 cm. the following...
Text Solution
|