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In the given figure, AB is a diameter, O...

In the given figure, AB is a diameter, O is the center of the circle and `angle OCB=50^@` then find `angle DBC`.

A

`80^@`

B

`100^@`

C

`120^@`

D

`140^@`

Text Solution

Verified by Experts

The correct Answer is:
B
(i) In triangle OBC,angles oppostive to equal sides are equal.
(ii) `angle ADB =angle ACB =90^@` (Since angle in a semi-circle is `90^@`).
(iii) `angle OCB=angle OBC and angle OAC =angle OCA ` (Angles opposite to equal sides).
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