If `sin theta=(a)/(b) `, then `cos theta ` and `tan theta ` in term of a and b are

Options

A. `(sqrt(b^(2)-a^(2)))/(b) and (b)/(sqrt(b^(2)-a^(2)))`
B. `(b)/(sqrt(b^(2)-a^(2))) and (a)/(sqrt(b^(2)-a^(2)))`
C. `(sqrt(a^(2)-b^(2)))/(a) and (b)/(sqrt(a^(2)-b^(2)))`
D. `(sqrt(b^(2)-a^(2)))/(b) and (a)/(sqrt(b^(2)-a^(2)))`

Answer

D

Explanation

Apply ` cos theta=(" Side adjacent to " theta )/(" Hypotenuse")`,
`tan theta =("Side opposite to " theta )/( " Side adjacent to " theta )`.