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sqrt(((1+sin2theta))/(1-cos^(2)theta))["...

`sqrt(((1+sin2theta))/(1-cos^(2)theta))["where" theta in [0,(pi)/(4)]]=`

A

`"cosec"^(2) theta `

B

`1`

C

`1+ cot theta `

D

`1+ tan theta `

Text Solution

Verified by Experts

The correct Answer is:
C
`1+ sin 2 theta =( sin theta + cos theta )2, " when" theta in[0,(pi)/(4)]`.
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