In a test by scoring `41.(2)/(3)%` of the maximum marks a student obtains 10 marks more than the pass marks .By scoring 30% of the maximum marks another student scores 4 marks less than the pass mark. Find the actual pass percentage

Options

A. `11.(2)/(3)%`
B. `22.(1)/(6)%`
C. `33.(1)/(3)%`
D. `66.(2)/(3)%`

Answer

C

Explanation

Let m be the maximum marks and p the pass marks .
(ii) Given `=(41.(2)/(3)xxm)/(100) =p+ 10 " and " .(30xxm)/(100) =p-4`
from the above equations we obtain the values of m and p.