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The magnetic field in a plane em wave is...

The magnetic field in a plane em wave is given by `B_y = 2 x 10 ^(-7) sin (pi x 10^3 x + 3 pi x 10^11 t )T Calculate the wavelength

A

`pi x 10^3`

B

`2 x 10^-3 m`

C

`2x 10^3 m`

D

`pi x 10^-3 m`

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The correct Answer is:
To solve the problem of finding the wavelength of the electromagnetic wave given by the magnetic field \( B_y = 2 \times 10^{-7} \sin(\pi \times 10^3 x + 3\pi \times 10^{11} t) \, T \), we can follow these steps: ### Step 1: Identify the wave equation format The magnetic field is given in the form: \[ B_y = B_0 \sin(kx + \omega t) \] where \( B_0 \) is the maximum magnetic field, \( k \) is the wave number, and \( \omega \) is the angular frequency. ### Step 2: Extract the wave number \( k \) From the given equation, we can identify the coefficient of \( x \) in the sine function: \[ k = \pi \times 10^3 \, \text{m}^{-1} \] ### Step 3: Relate wave number \( k \) to wavelength \( \lambda \) The wave number \( k \) is related to the wavelength \( \lambda \) by the formula: \[ k = \frac{2\pi}{\lambda} \] We can rearrange this to find \( \lambda \): \[ \lambda = \frac{2\pi}{k} \] ### Step 4: Substitute the value of \( k \) into the wavelength formula Substituting the value of \( k \): \[ \lambda = \frac{2\pi}{\pi \times 10^3} \] ### Step 5: Simplify the expression The \( \pi \) in the numerator and denominator cancels out: \[ \lambda = \frac{2}{10^3} = 2 \times 10^{-3} \, \text{m} \] ### Step 6: Final answer Thus, the wavelength \( \lambda \) of the electromagnetic wave is: \[ \lambda = 2 \times 10^{-3} \, \text{m} \, \text{or} \, 2 \, \text{mm} \] ---
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