In the circuit (Figure ) , the current it to be measured. What is the value of the current if the ammeter shown (a) is galvanometer with a resitance `R_(G) = 60,00 Omega`, (b) is a galvanometer by a shunt resitance `r_(s) = 0.02 omega` (c) is an ideal ammter with zero resitance ?

Explanation

Total resistance in the circuit is
`R_(G) + 3 = 63 omega` Hence `I = (3)/(63)` = 0.02 `omega`
Total resistance in the circuit is `0.02 omega + 3 omega = 3.02 Omega` Hence `I= (3)/(3.02)` = 0.99 A
c. For the ideal ammerter with zero resistance `I = (3)/(3) = 1.00 A`