The length and breadth of a rectangle are `(5.7 pm 0.1)` cm and `(3.4 pm 0.2)` cm respectively. Calculate the area of the rectangle with error limits.

Explanation

Lenght `l=(5.7 pm 0.1)` cm
Breadth `b = (3.4 pm 0.2)` cm
Area A with error limit = `A pm DeltaA=?`
Area A = `lxxb = 5.7 xx 3.4 = 19.38 = 19.4 "cm"^(2)`
`(DeltaA)/(A) = (Deltal)/(l) + (Deltab)/(b) , DeltaA = ((Deltal)/(l) + (Deltab)/(b))A`
`DeltaA = ((0.1)/(5.7) + (0.2)/(3.4)) 19.4 = (0.0175 + 0.0588) xx 19.4 = 1.48 = 1.5`
Area with error limit A = `(19.4 pm 1.5) "cm"^(2)`