The parallax of a heavenly body measured from two points diametrically opposite on equator of Earth is `2^(1)`. Calculate the distance of the heavenly body. [Given radius of the Earth = 6400 km][1" = `4.85 xx 10^(-6)` rad]

Explanation

Angle `theta = 2^(1) = 2 xx 60.. = 120.. = 120 xx 4.85 xx 10^(-6)` rad
`theta = 5.82 xx 10^(-4)` rad,
The distance of heavenly body
`D = (d)/(theta) = (12800xx10^(3))/(5.82xx10^(-4))`
`D = 2.19 xx 10^(10)` m