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Show that a screw gauge of pitch I mm an...

Show that a screw gauge of pitch I mm and 100 divisions is more precise than a vernier caliper with 20 divisions on the sliding scale.

Text Solution

Verified by Experts

Least count of screw gauge = `("Pitch")/("No. of divisions") = (1 mm)/(100) = 0.01` mm
Least count of vernier caliper = `(1)/(20)` mm = 0.05 mm
As shown, the least count of screw gauge is lesser than vernier caliper, hence screw gauge more precise.
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Knowledge Check

  • The diameter of the steel ball is measured using a vernier caliper which has divisions of 0.1 cm on its main scale nad 10 division of its vernier scale match 9 division on the main scale. Three such measurements for a ball are as follows. If the zero error is 0.03cm , then mean corrected diameter is ............. cm.

    A
    0.56
    B
    0.53
    C
    0.59
    D
    0.52

  • The diameter of the steel ball is measured using a vernier caliper which has divisions of 0.1 cm on its main scale nad 10 division of its vernier scale match 9 division on the main scale. Three such measurements for a ball are as follows. If the zero error is 0.03cm , then mean corrected diameter is ............. cm.

    A
    0.56
    B
    0.53
    C
    0.59
    D
    0.52

  • (I) Least count of screw gauge is 0.01 mm (II) Least count of vernier calliper is 0.1mm Which one is correct?

    A
    I only
    B
    II only
    C
    Both are correct
    D
    None

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