The length of a rod as measured in an experiment was found to be 2.48 m, 2.46 m, 2.49 m, 2.50 m and 2.48 m. Find the average length, absolute error and percentage error. Express the result with error limit.

Explanation

Average length `= (2.48+2.46+2.49+2.50+2.48)/(5) = (12.41)/(5) = 2.48` m
Mean absolute error `= (0.00+0.02+0.01+0.02+0.00)/(5) = (0.05)/(5) = 0.01` m
Percentage error = `(0.01)/(2.48) xx 100% = 0.04 xx 100% = 0.40%`
Correct length = `(2.48 pm 0.01)` m
Correct length `= (2.48 m pm 0.40%)`