If a stone tied at the one end of a string of length 0.5 m is whirled in a horizontal circle with a constant speed` 6 ms^(-1)` , then the acceleration of the stone is

Options

A. `12 ms^(-2)`
B. `36 ms^(-2)`
C. `2pi^2 ms^(-2)`
D. `72 ms^(-2)`

Answer

D

Explanation

Centripital acceleration ` =(v^2)/(r ) = (6^2)/(0.5) = (36)/(0.5) =72 ms^(-2)`