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A bomb of 10 kg at rest explodes into tw...

A bomb of 10 kg at rest explodes into two pieces of mass 4 kg and 6 kg. If the velocity of 4 kg mass is `6 ms^(-1)` then the velocity of 6 kg is

A

`4ms^(-1)`

B

`6ms^(-1)`

C

`24 ms^(-1) `

D

`2.2 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
According to law of consevation of momentum
`m_1v_1 + m_2 v_2 = 0`
` v_2 = (m_1v_1)/(m_2) = - (4 xx 6)/(6 ) = - 4ms^(-1)`
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