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A variable force F=kx^(2)acts on a parti...

A variable force `F=kx^(2)`acts on a particle which is initially at rest. Calculate the work done by the force during the displacement of the particle from `x=0 m "to" x= 4m`. (Assume the constant `k=1Nm^(-2)`)

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The correct Answer is:
Work done, `W=underset(x_i)overset(x_f)intF(x)dx=kunderset(0)overset(4)intx^(2)dx=64Nm`
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