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A body of mass 5kg is thrown up vertical...

A body of mass `5kg` is thrown up vertically with a kinetic energy of `1000J`. If acceleration due to gravity is `10ms^(-2)`, find the height at which the kinetic energy becomes half of the original value.

Text Solution

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Mass `m=5kg ,K.E. E=1000J ,g=10ms^(-2)`
At a height `h`, mgh=`E/2`
`5xx10xxh=(1000)/2`
`h=(500)/(50)=10m`
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