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The momentum of the body is doubled, wha...

The momentum of the body is doubled, what % does its K.E. change ?

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`K.E.=p^(2)/(2m)"when p is doubled K.E.as K.E.becomes 4 times"`
`therefore%"Increase in K.E."=(triangleK.E.)/(K.E)xx100(4K.E-K.E.)/(K.E)XX100=3XX100=300%`
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FULL MARKS-WORK, ENERGY AND POWER-Additional Question Solved (II. Short Answer Questions)
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