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An elevator which can carry a maximum lo...

An elevator which can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a constant speed of 2 ms. The frictional force opposing the motion is 4000 N. Determine the minimum power delivered by the motor to the elevator in watts as well as in horse power

Text Solution

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Downward force on the elevator is :
`F=mg+f=22000N`
`therefore "power supplied by motor to balance this force is"`:
`p=F_(v)=44000W=(44000)/(746)=59hp`
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