Water rises in a capillary tube to a height of 2.0 cm. In another capillary tube whose radiuus is one third of it, how much the water will rise?

Explanation

From equation , we have
`h prop 1/r implies hr = "constant"`
Consider two capillary tubes with radius `r_1 and r_2` which on placing in a liquid, capillary rises to height `h_1 and h_2`, respectively, Then ,
`h_1 r_1 = h_2r_2` = constant
`implies h_2 = (h_1r_1)/(r_2) = ((2 xx 10^(-2) m)xxr)/(r ) implies h_2 = 6 xx 10^(-2) m`.