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A block of Ag of mass x kg hanging from ...

A block of Ag of mass x kg hanging from a string is immersed in a liquid of relative density 0.72. If the relative density of Ag is 10 and tension in the string is 37.12 N then compute the mass of Ag block.

Text Solution

Verified by Experts

From the terminal velocity condition, `F_G - U = F " " F = T , m = x`
`mg - mg ((rho_w)/(rho)) = T`
`mg[1 - (0.72)/10] = 37.12`
`9.8x [1 - 0.072] = 37.12`
`9.0944 x = 37.12`
`x = 4kg`
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