An ideal liquid is flowing in a cylindrical tube of internal diameter 4 cm with a velocity of `5 ms^(-1)`. If this tube is connected to another tube of internal diameter 2 cm, then the velocity of the liquid in the second tube will be ?

Explanation

According to the equation of continuity
`a_2v_2 = a_1v_1 , d_2^2 v_2 = d_1^2v_1`
`v_2 = ((d_1)/(d_2))^(2) xx v_1 = (4/2)^2 xx 5`
`v_2 = 20 ms^(-1)`.