Calculate the height to which water will rise in capillary tube of 1.5 mm diameter. Surface tension of water is `7.4 xx 10^(-3) Nm^(-1)`.

Explanation

Here, `r = (1.5)2 = 0.75 mm = 0.75 xx 10^(-3) m`
`sigma = 7.4 xx 10^(-3) Nm^(-1)`
For water, `rho = 10^3 m^(-3)`
Angle of contact `" " theta = 0^@`
`h = (2 sigma cos theta)/(r rho g) = (2 xx 7.4 xx 10^(-3) xx cos 0^@)/(0.75 xx 10^(-3) xx 10^3 xx 9.8)`
`h = 0.002014 m`