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The length of a second's pendulum on the...

The length of a second's pendulum on the surface of the Earth is `0.9m`. The length of the same pendulum of surface of planet X such that the acceleration of planet X is n times greater than the Earth is :

A

0.9n

B

`(0.9)/(n)m`

C

`0.9n^(2)m`

D

`(0.9)/(n^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
Second.s pendulum on the surface of planet,
Time period, `T=2sec`
`T=2pisqrt((l)/(g))`
`2=2pisqrt((l)/(ng)),l^(2)=pi^(2)((l)/(ng)),l=(9.8n)/((3.14)^(2))`
`l=(9.8n)/(9.8596),l=0.9n`
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