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A simple pendulum is suspended from the ...

A simple pendulum is suspended from the roof of a school bus which movies in a horizontal direction with an acceleration a, then the time period is :

A

`T=prop(1)/(g^(2)+a^(2))`

B

`T=prop(1)/(sqrt(g^(2)+a^(2)))`

C

`Tpropsqrt(g^(2)+a^(2))`

D

`Tprop(g^(2)+a^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
According to law of acceleration, the time period of simple pendulum
`Tprop(1)/(sqrt(g))`
From phythagoras theorem, `g.=g^(2)+a^(2)`
`g.^(2)=sqrt(g^(2)+a^(2))`
`Tprop(1)/(sqrt((sqrt(g^(2)+a^(2))))),Tprop(1)/(g^(2)+a^(2))`
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